Ok here is my redo....and please tell me how to do the default gateway because I have no I idea I put the 172.16.0.25 and 172.16.0.45 by the router to show the default gateway unless thats wrong?

you've probably got everything back on one network again, cant tell with no subnet masks

if you don't want a WAN, replace the lightning bolt with a line,
bolts typically define telco circuits

we've already determined you need 3 subnets, which ones will you use?
show network, subnet mask (use cidr notation i.e. /24 etc.) and default gateway for each.

for ease of documentation, default gateways are usually either the first usable IP or last usable IP in a network, although any IP is valid, stick with conventions.

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"If you're good at anticipating the human mind. It leaves nothing to chance."
-Jigsaw

Hope this is right because I been up all night trying to figure this out.

It seems like you are struggling with the subneting/IP addressing of this project. Id advise spending a little time reading up on subneting and IP addressing of networks. Also do some research on basic network design and look at some examples of how others suggest to lay out a similar network.

To point you in the right direction:
You need three non-overlapping subnets in this network
1)RouterA/SwitchA/Host1 and 2 on their own subnet. Use a /24 mask
a)All host should point to RouterA for a Gateway
2)RouterB/SwitchB/Host3 and 4 on their own subnet. Use a /24 mask
a)All host should point to RouterB for a Gateway
3)RouterA - RouterB link. Use a /30 mask


Thats as much as I will give you without doing the work for you.

Hope this helps

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http://blog.movingonesandzeros.net/

So I need 6 subnets in all like this:
172.16.0.0 255.255.255.0 172.16.0.255 172.16.0.1 172.16.0.254
172.16.1.0 255.255.255.0 172.16.1.255 172.16.1.1 172.16.1.254
172.16.2.0 255.255.255.0 172.16.2.255 172.16.2.1 172.16.2.254
172.16.3.0 255.255.255.0 172.16.3.255 172.16.3.1 172.16.3.254
172.16.4.0 255.255.255.0 172.16.4.255 172.16.4.1 172.16.4.254
172.16.5.0 255.255.255.0 172.16.5.255 172.16.5.1 172.16.5.254

Or just two that I highlighted?

Re-read my last post it tells you specifically the number of subnets you need...

The subnets you listed are correct /24 subnets.

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http://blog.movingonesandzeros.net/

Think I got it now????!!! Switch should not have an IP my bad.

1)RouterA/SwitchA/Host1 and 2 on their own subnet. All use a 172.16.1.254/24
a)All host should point to RouterA for a Gateway - Default Gateway is 172.16.1.254/24
2)RouterB/SwitchB/Host3 and 4 on their own subnet. All use a 172.16.2.254/24
a)All host should point to RouterB for a Gateway - Default Gateway is 172.16.2.254/24
3)RouterA - RouterB link. using a 172.16.0.1/30 - 172.16.0.2/30

It should be right now.

Tweaked it some more and added some more stuff.

There you go!! Exactly how I would do it.

But do put IPs on the switches in the LAN subnets. You dont need them for traffic flow but you will need them IP'ed for management purposes.

Also make sure you understand why you are using a /30 on router-to-router PTP link and your set!

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http://blog.movingonesandzeros.net/

Too much information. Why do you need broadcast, first host, and last host? If you put /24 you know all that info in a single /24 statement


Sent on the move...

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www.mellowd.co.uk/ccie/

If its homework there is never TMI

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http://blog.movingonesandzeros.net/

why you are using a /30 on router-to-router PTP link? Because you dont want to use more IPs than needed and a /30 has two useable IPs. Is that right?

And Yes its homework and take a look at the final diagram.

Looks good to me.

As an extra thought, when laying out your IP addressing you usually want to group similar devices together. This helps with organization.

For example:
Network equipment - 172.16.x.250 - 254
Servers - 172.16.x.1 - 20
Workstations/end users - 172.16.x.50 - 150 (usually a DCHP range)
Printers - 172.16.x.200 - 210

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http://blog.movingonesandzeros.net/

OK thanks will remember that...I'm here doing some virtual labs on CCNA Virtual Lab, Platinum Edition...trying to get familiar.

man, get Dia if you don't have access to Visio. this trial statement is really annoying
https://live.gnome.org/Dia

I agree with this - almost..

I prefer to use binary-based ranges rather than decimal. If my servers were addressed at .1 through .20, I might have to work a bit harder to define ACLs or network ranges. If I defined a range of 32 addresses, for example, I could specify that servers were in the range 172.16.x.0/27. It isn't a "subnet" but a range of addresses that can be identified by standard subnet nomenclature and treated as such.

Since I'm involved in the server side as well, we often take it a bit further and divide our servers network up (usually one or more /24 subnets) and group common types of servers in their own IP ranges. In a small network, we might put all AD servers at 8-15, file/print at 16-31, and so on.. Again, this makes setting access and firewall rules easier. By allocating a larger block than we actually need, we have room to grow as well.

It's really personal preference, but establishing a standard that you understand early on is helpful to seeing the big picture.

Glenn

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Lost: Rocket, appx 8' tall, Green w/ yellow fins, nose, and computer bay.. Last seen streaking skyward in NY

Thanks Glenn will do, keep all of this in mind as I move forward thanks again.